
The fundamental equations magnetostatics are linear equations,
(SI units) |
|
The principle of superposition holds.
The magnetostaticstatic force on a particle with charge q is
(SI units),
(Gaussian units).
| Drift velocity: | ||
| Current density: | ||
| Current: |
The continuity equation is
In statics
.
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Currents and Circuits |
|||
|
I = ňj×dA or I = dQ/dt | ||
|
R = DV/I | ||
|
R = rl/A | ||
|
P = IDV = I2R = (DV)2/R, | ||
|
R = R1 + R2 + R3 | ||
|
1/R = (1/R1) + (1/R2) + (1/R3) |
| Kirchhoff's first rule : (Junction rule) At any junction point in a circuit where the current can divide, the sum of the currents into the junction must equal the sum of the currents out of the junction. (This is a consequence of charge conservation.) | |
| Kirchhoff's second rule : (Loop rule) When any closed circuit loop is traversed, the algebraic sum of the changes in the potential must equal zero. (This is a consequence of conservation of energy.) |
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(SI units) |
(Gaussian units) |
In situations with enough symmetry Ampere’s law alone can be used to find the
magnitude of B. The flux of B through any closed
surface is zero. ![]()
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| (SI units) | (Gaussian units) | |
| For filamentary currents we have | ||
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.
A is not unique.
, with
an arbitrary scalar field and
C an arbitrary constant vector is also a vector potential for the
same field.
In magnetostatics we choose
Then
| (SI units) | Gaussian units) | |
The uniqueness theorem:
If if the current density j is specified throughout a volume V and A or its normal derivatives are specified at the boundaries of a volume V, then a unique solution exists for A inside V.
Or, if the current density j is specified throughout a volume V and and either A or B are specified at the boundaries of a volume V, then a unique solution exists for B inside V.
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| (SI units) | (Gaussian units) | |
| A is continuous across the boundary. | A is continuous across the boundary. |
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| (SI units) | (Gaussian units) | |
| For filamentary currents we have | ||
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| (SI units) | (Gaussian units) | |
| The vector potential of a magnetic dipole at the origin is | ||
| The magnetic field of a magnetic dipole at the origin is | ||
The energy of a magnetic dipole in an external
magnetic field is
This is the mechanical work done to bring the dipole from infinity to its
present position.
The force on a dipole
is
.
The torque
on a dipole is
.
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