
When the net force acting on an object is zero, the net work done by all the forces acting on the object is zero. When the net force acting on an object is not zero, then the net work done on the object is Wnet = Fnet· d. When a net force acts on an object, then the object accelerates, it changes its velocity.
Can we express the work done by the net force in terms of this change in velocity?
Assume an object is moving along a straight line, and a constant force Fnet = ma is acting on the object. Then W = ma·d. The work is proportional to the component of the acceleration a||, parallel to the direction of the displacement. This component of the acceleration causes a change in speed, a|| = (vf-vi)/Dt. Therefore
W = md(vf-vi)/Dt.
The distance traveled is the average speed times Dt,
d = Dt(vf+vi)/2.
Therefore
W = m(vf-vi)(vf+vi)/2 = (1/2)m(vf2-vi2).
We can express the net wok done on the object in terms of the change in the quantity (1/2)mv2. We define the (translational) kinetic energy of the object as K = (1/2)mv2. The net work done on the object is equal to the change in the kinetic energy of the object.
Wnet = Kf - Ki = DK.
This is called the work-kinetic energy theorem.
| Assume that together with your partner you want to win a soapbox race. You are allowed to push the cart with your partner in it for a distance of 5 m to give it some initial speed. You are pushing as hard as you can. You do work on the cart. The work you do is the average force you exert times the distance the cart moves in the direction of the force, W = F(5m). You transfer energy to the cart. The cart gains kinetic energy. |
Kinetic energy increases with the square of the speed. Neglecting friction, an engine does four times as much work to make a car reach a speed of 60 miles/h as to make it reach a speed of 30 miles/h. When the speed of a car is doubled, its kinetic energy increases by a factor of four.
| A 3kg mass has an initial velocity v0 = (6i-2j)m/s. (a) What is its kinetic energy at this time? (b) Find the total work done on the object if its velocity changes to (8i+4j)m/s. (Hint: Remember that v2 = v·v.)
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The gravitational potential energy Ug is defined as the negative of the work done by the gravitational force, or the work done by an applied force canceling the gravitational force, in displacing an object from a reference position. If the gravitational force acting on an object is pointing in the -y direction with constant magnitude mg, and the reference position is at y = 0, then Ug = mgy.
The zero of the gravitational potential energy, i.e. the reference position, is chosen arbitrarily. However a difference in gravitational potential energy
DUg = mgDy = mg(yf - yi)
is uniquely defined.
The gravitational potential energy gained by an object being lifted is equal to the work done on the object by an applied force, which exactly cancels gravity. The applied force does positive work. When the object is being lifted, the gravitational force does negative work. The gravitational potential energy can be converted back into other forms by letting the gravitational force do positive work. If we let the object fall towards the ground it will loose potential energy and gain kinetic energy.
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The gravitational potential energy does not depend on the path.
| We do the same work lifting the motorcycle straight up onto the bed of the truck or rolling it up a ramp. |
The gravitational force near the surface of the earth points vertically downward. We can approximate any path between two points P1 and P2 by arbitrarily small vertical and horizontal segments.

The total horizontal and the total vertical displacement are the same for each path. The gravitational force does no work along the horizontal segments of the path, since here it is perpendicular to displacement vector. It does work Wi = -mgDyi along each vertical segment of length Dyi. The total work done by the gravitational force is W = -mgDytotal = -mgh. The change in potential energy is Ug = mgh.
A potential energy function is a function of the position of an object. It can be defined only for conservative forces. A force is conservative if the work it does on an object between any two points is independent of the path taken by the object. The gravitational force is a conservative force. The potential energy function associated with the gravitational force near the surface of the earth is Ug = mgy if the reference point is chosen at y = 0. (Ug only depends on the position of an object, not on how the object reached that position.)
Another example of a conservative force is the force exerted by a spring. The elastic potential energy function is Us = (1/2)kx2, where x is the displacement from equilibrium, if the reference point is chosen to be x = 0. (Us only depends on the position of an object, not on how the object reached that position.)
| Consider an isolated, conservative system, for example two masses connected by a spring.
The two masses can vibrate against each other, thereby alternately stretching and
compressing the spring. The velocity of the masses is zero when the displacement of the
spring has its maximum positive or negative value. The system has maximum potential energy
and no kinetic energy, Umax = (1/2)kx2max. When the displacement of the spring from its equilibrium position is zero the masses have maximum speed. The system has maximum kinetic and no potential energy, Kmax = (1/2)mv2max. Umax = Kmax. At intermediate values for the displacement the system has both kinetic and potential energy. We have U + K = Umax = Kmax. |
For an isolated, conservative system, i.e. an isolated system only acted on by internal, conservative forces, the sum of the kinetic energy and potential energy is constant.
Ki + Ui = Kf + Uf.
We define
E = K + U,
where E = mechanical energy. The mechanical energy of an isolated conservative system is conserved. Conservation of mechanical energy is a powerful tool for solving physics problems.
From a 50m high platform a 0.1kg stone is thrown straight upward with initial speed
5m/s. What is it speed 10 m above the ground?
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For an isolated, conservative system E is constant, dE/dt = 0. Assume an object is moving along the x-axis.
dK/dt = d(mv2/2)/dt = mv(dv/dt) = mvax =
Fxv.
dU/dt = (dU/dx)(dx/dt) = (dU/dx)v.
dK/dt + dU/dt = 0
implies
Fxv + (dU/dx)v = 0
or
Fx = -dU/dx.
The conservative internal force acting between parts of the system equals the negative derivative of the potential energy associated with that system.
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Microscopically all known forces are conservative. Therefore, microscopically, all energy is either kinetic or potential energy, and, if the system under consideration is the whole universe, the total energy of the universe is conserved.
Work is the conversion of one form of energy into another. Macroscopically, there are forms of energy that can easily and completely be converted into other forms. We call these forms ordered energy. Gravitational potential energy is an example of ordered energy. The gravitational potential energy stored in a car on top of a hill is converted into kinetic energy as it rolls towards the bottom of the hill. Hydroelectric plants convert the gravitational potential energy stored in the water in a reservoir into electric energy. Kinetic energy also can be easily converted. Kinetic energy is the energy an object has because it is moving.
There is however a form of energy, thermal energy, which cannot easily and completely converted into other forms. Thermal energy is disordered energy. The individual atoms and molecules that make up an object have potential and kinetic energy, but they move in a random fashion about their equilibrium position in the object, so that the object as a whole remains at rest. The more kinetic energy is stored in the random motion of the atoms or molecules, the higher is the temperature of the object.
Macroscopically, forces that do work converting ordered energy into disordered energy are non-conservative forces. The work done by macroscopically non-conservative forces on an object as it moves from position P1 to position P2 depends on the path of the object. Friction is an example of such a non-conservative force. The work done by the force of friction converts ordered energy into thermal energy.
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When a system is acted on by an external force, then energy can be transferred into or out of the system. An external force can do work against internal forces and change the potential energy of the system or it can be a net force changing the kinetic energy of the system. The work Wapp done by the external force on a conservative system may be written as Wapp = DK + DU. The applied external force can be a conservative or a non-conservative force.
A 70kg diver steps off a 10m tower and drops straight down into the
water. If he comes to rest 5m below the surface of the water,
determine the average resistance force exerted on the diver by the water.
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| The coefficient of friction between the 3kg mass and the surface in the
figure below is 0.4. The system starts from rest. What is the
speed of the 5kg mass when it has fallen 1.5m?
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Links:
| Downhill Skiing | |
| Roller Coaster | |
| Dart | |
| Pendulum | |
| Incline | |
| Hot Wheels | |
| Skid | |
| Slide | |
| Potential energy |
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Work is done by a force on an object when the object moves in the direction of the force. Power is a measure of how quickly this work is done, it is the rate at which work is done.
P = DW/Dt = average power
P = dW/dt = instantaneous power
| You can load a scientific instrument to measure wind speed into your backpack and hike up a mountain, or you can load it into your car and drive up the mountain. Either way, you do the same amount of work on the instrument. This work is equal to mgh, where mg is the weight of the instrument and h is the difference in altitude. The power, the rate at which you do this work, however, is different. The hike takes 4 hours, while the drive takes 30 minutes. |
The SI unit of power is Joule/s = Watt. (J/s = W.) Often used units are kilowatt (kW), megawatt (MW), and milliwatt (mW).
1 kW = 1000 W.
1MW = 1000000 W = 106 W.
One horsepower (hp) = 745.7 W.
When you pay your electric bill, you pay for each kilowatt-hour (kWh) used.
Kilowatt-hour is a unit of energy or work, not power.
1 kWh = 1kW 1hour = 1000 J/s 3600s = 3600000 J = 3.6 ´ 106
J
The instantaneous power is P = dW/dt. We have
dW = F·dr.
Therefore we may write
P = F·dr/dt = F·v.
A certain automobile engine delivers 30hp (2.24´104
W) to its wheels when moving at a constant speed of 27m/s (~60mi/h).
What is the resistive force acting on the automobile at that speed?
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Links to other Web materials:
| Potential Energy and Fields |
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